METAL OXIDE: When a Metal Reacts With and Gains Oxygen
sCOMBUSTION OF METAL OXIDES |
Diagram showing the Apparatus needed to find the Formulae of a Metal Oxide by Combustion |
METHOD:
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WORKING OUT EMPIRICAL FORMULA / FORMULAE: Mass of Metal: Subtract mass of crucible from Metal and mass of empty crucible Mass of Oxygen: Subtract mass of Metal used from the mass of Magnesium Oxide STEP 1 - Divide each of the Two Masses by the Relative Atomic Masses of Elements STEP 2 - Simplify the Ratio Metal Oxygen Mass x y Mole x / Mr y / Mr = a = b Ratio a : b STEP 3 - Represent the Ratio into the ‘ Metal O ‘ (e.g, MgO) |
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REDUCTION OF METAL OXIDES |
Diagram showing the Apparatus needed to find the Formulae of a Metal Oxide by Reduction |
METHOD:
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WORKING OUT EMPIRICAL FORMULA / FORMULAE: Mass of Metal: Measure mass of remaining Metal Powder Mass of Oxygen: Subtract mass of the remaining Metal Powder from the mass of Metal Oxide STEP 1 - Divide Each of the Two Masses by the Relative Atomic Masses of Elements STEP 2 - Simplify the Ratio Metal Oxygen Mass a b Mole a / Mr b / Mr = x = y Ratio x : y STEP 3 - Represent the Ratio into the Form ‘ xO ‘ (e.g, MgO) |
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